![]() The client generates the 48-byte premaster secret by concatenating the protocol version (2 bytes) and some bytes that the client generates randomly (46 bytes). How will it match the value the client sent previously? Can someone please explain this? Thank yuou! Is there any API to compute this value? Matches the value transmitted by the client in the client Premaster secret, the server should check that this value Used to detect version roll-back attacks. The latest (newest) version supported by the client. Is a variant of the client key exchange message, not a message in Result in an encrypted premaster secret message. Key provided in a server key exchange message, and sends the ![]() The public key from the server's certificate or the temporary RSA ![]() If RSA is being used for key agreement and authentication, theĬlient generates a 48-byte premaster secret, encrypts it using From RFC 2246: (TLSv1.0) RSA encrypted premaster secret message ![]() I believe that it uses some combination of the random values sent in the hello messages. ![]()
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